0=-0.03x^2+1.8x-25

Solution for 0=-0.03x^2+1.8x-25 equation:

0=-0.03x^2+1.8x-25

We move all terms to the left:

0-(-0.03x^2+1.8x-25)=0

We add all the numbers together, and all the variables

-(-0.03x^2+1.8x-25)=0

We get rid of parentheses

0.03x^2-1.8x+25=0

a = 0.03; b = -1.8; c = +25;
Δ = b2-4ac
Δ = -1.82-4·0.03·25
Δ = 0.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.8)-\sqrt{0.24}}{2*0.03}=\frac{1.8-\sqrt{0.24}}{0.06}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.8)+\sqrt{0.24}}{2*0.03}=\frac{1.8+\sqrt{0.24}}{0.06}
$